Use the chain rule to differentiate y=1/x^2-2x-1
First we will rewrite y so it is written with a power: y=1/x2-2x-1=(x2-2x-1)-1 Now let u=x2-2x-1 => du/dx = 2x -2 Writing y in terms of u: y=u-1 => dy/du= -u-2 = - 1/u2 using the chain rule: dy/dx = dy/du x du/dx =-1/u2 x (2x-2) substituting back in the value of u: =-(2x-2)/(x2-2x-1)2 = dy/dx
AP
Related Maths A Level answers
All answers ▸Let p(x) = 30 x^3 -7 x^2 - 7 x + 2. Prove that (2x + 1) is a factor of p(x) and factorise p(x) completely.
Find the stationary points of the curve y (x)= 1/3x^3 - 5/2x^2 + 4x and classify them.
The equation: x^3 - 12x + 6 has two turning points. Use calculus to find the positions and natures of these turning points.
How do I work out (2+y)^4 using the binomial expansion?