Use the chain rule to differentiate y=1/x^2-2x-1
First we will rewrite y so it is written with a power: y=1/x2-2x-1=(x2-2x-1)-1 Now let u=x2-2x-1 => du/dx = 2x -2 Writing y in terms of u: y=u-1 => dy/du= -u-2 = - 1/u2 using the chain rule: dy/dx = dy/du x du/dx =-1/u2 x (2x-2) substituting back in the value of u: =-(2x-2)/(x2-2x-1)2 = dy/dx
AP
Related Maths A Level answers
All answers ▸How to solve polynomials
The cubic polynomial f(x) is defined by f(x) = 2x^3 -7x^2 + 2x + 3. Given that (x-3) is a factor of f(x), express f(x) in factorised form.
When you integrate a function why do you add a constant?
Express (5x + 4)/(x +2)(x - 1) in partial fractions.