Solve the simultaneous equation: y+4x+1=0 y^2+5x^2+2x=0
Rearrange the first equation to get y on its own: y=-(1+4x) Substitute into the second equation: (1+4x)(1+4x)+5x^2+2x=0 21x^2+10x+1=0 Substite into the quadratic formula to solve (-b+/-(b^2-4ac)^0.5)/2a
GL
Related Maths A Level answers
All answers ▸Given that y=ln([2x-1/2x=1]^1/2) , show that dy/dx= (1/2x-1)-(1/2x+1)
Find the equation of the normal to the curve 2x^3+3xy+2/y=0 at the point (1,-1)
The equation of a curve is xy^2= x^2 +1. Find dx/dy in terms of x and y, and hence find the coordinates of the stationary points on the curve.
A ball is thrown vertically upwards with a speed of 24.5m/s. For how long is the ball higher than 29.4m above its initial position? Take acceleration due to gravity to be 9.8m/s^2.