Solve the following simultaneous equations: 3x + 5y = -4 and -2x + 3y = 9

Label the equations 1 and 2 We want to make it so the x are the same number - therefore we have to find a common multiple of 2 and 3 - this is 6 Therefore the equations turn into: 1) 6x + 10y = -8 2) -6x + 9y = 27 Add together: 19y = 19 Therefore y = 1 Plug back into equation 1: 3x + 5 = -4 Therefore x = -3 Check with equation 2: -2(-3) + 3(1) = 9

KP
Answered by Krishnaa P. Maths tutor

4839 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the nature of the turning points of the graph given by the equation x^4 +(8/3)*x^3 -2x^2 -8x +177 (6 marks)


Use the substitution u = cos 2x to find ∫(cos^2*(2x) *sin3 (2x)) dx


Solve the following simultaneous equations y + 4x + 1 = 0, y^2 + 5x^2 + 2x = 0


solve for x, in the form x = loga/logb for 2^(4x - 1) = 3^(5-2x) (taken from OCR June 2014 C2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences