Solve the following simultaneous equations: 3x + 5y = -4 and -2x + 3y = 9

Label the equations 1 and 2 We want to make it so the x are the same number - therefore we have to find a common multiple of 2 and 3 - this is 6 Therefore the equations turn into: 1) 6x + 10y = -8 2) -6x + 9y = 27 Add together: 19y = 19 Therefore y = 1 Plug back into equation 1: 3x + 5 = -4 Therefore x = -3 Check with equation 2: -2(-3) + 3(1) = 9

KP
Answered by Krishnaa P. Maths tutor

5265 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Use the substitution u = 2^x to find the exact value of ⌠(2^x)/(2^x +1)^2 dx between 1 and 0.


Differentiate cos(2x)/(x) with respect to x


Solve the simultaneous equations: (1) y – 2x – 4 = 0 , (2) 4x^2 + y^2 + 20x = 0


What is 'differentiation'?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning