Solve (x+2)/3x + (x-2)/2x = 3
In order to solve this equation we need to rearrange it to have all of the variables on one side of the equals sign and the constants on the other. We do this by multiplying each term by the denominator of one of the fractions. First we multiply each term by 3x to obtain x + 2 + 3x(x-2)/2x = 9x. There is an x on the top and bottom of the fraction term so we can simplify further to get x + 2 + 3x/2 -3 = 9x which when we collect like terms becomes 13x/2 = -1. Dividing both sides by 13/2 gives the answer: x = -2/13
AY
Related Maths GCSE answers
All answers ▸Here is a right-angled triangle (base = 8cm and height = 9cm) and a rectangle (length = 16cm). The area of the rectangle is 6 times the area of the triangle. Work out the width of the rectangle.
How can you add and subtract fractions with surds in them?
What are the roots of the graph of this equation: x^2 + 9x + 18 = 0
differentiate x^3(1+x)^5 with respect for x