How would you determine what sort of stationary point this curve has? x^3 - 6x^2 + 9x - 4

I would differentiate it and then turn it into an equation to find the points where the gradient equals zero. With these points at hand, I would take a second derivative, this tells me how the gradient changes with x and from this I would plug in my known points to see what value pops out. If it's postive I know that this stationary point is a minimum and if it's negative I know that this stationary point is a maximum. If the answer is zero then this hints at (but doesnt al+ways mean) a point of inflection. dy/dx = 3x2 - 12x + 9 3x2 -12x + 9 = 0 x2 - 4x + 3 = 0 (Dividing both sides with 3) (x - 3)(x-1) = 0, x=3 and x=1. d2y/dx= 6x -12 When x = 1, d2y/dx2 = -6 therefore a maximum When x = 3, d2y/dx2 = 6 therefore a minimum.

WM
Answered by William M. Maths tutor

4989 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

(Core 2) Show that the region bounded by the curve y = 7x+ 6 - (1/x^2), the x axis and the lines x = 1 and x = 2 equals 16


Express 4sin(x)+6cos(x) in terms of Rsin(x+a) where R and a are constants to be determined (a should be given in rad).


solve the inequality x^2+4x-21>0


Show that r^2(r + 1)^2 - r^2(r - 1)^2 ≡ 4r^3.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences