solve: x^2= 4(x-3)^2

x^2= 4(x^2 - 6x + 9)

x^2= 4x^2- 24x + 36

3x^2 - 24x + 36= 0

(x-2)(x-6)=0

x= 2 or x=6

GK
Answered by Ghazn K. Maths tutor

3414 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify: 2x + 6y + 2y - x


expand the brackets: (x+3)(x+2)


161/5 x 26x =


How do I solve simultaneous equations when one is quadratic? For example 3x^2 -2y = 19, 6x-y-14=0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning