Solve x^2+8x-5 = 0 by completing the square.

x2 + 8x = (x + 4)2 - 16, so x2 + 8x - 5 = (x + 4)2 - 16 - 5 = (x + 4)2 - 21, so then (x + 4)2 - 21 = 0 (x + 4)2 = 21 -----> x + 4 = √21 -------> x = -4 + √21                               x = -4 - √21

SJ

Related Maths GCSE answers

All answers ▸

Write 𝑥²+6𝑥+11 in the form (𝑥+a)²+b.


solve the following equation: 7x + 8 = 2(6x -2)


solve z^4=2(1+isqrt(3)) giving roots in form r(cos(theta)+isin(theta))


What's the quadratic formula used for?