Given that y = (( 4x + 1 )^3)sin(2x), find dy/dx.

This is an example of the chain rule.

The chain rule is the following: if y = uv, then dy/dx = udv/dx + vdu/dx

So in this case, u = ( 4x + 1)^3, v = sin(2x)

du/dx = (3)(4)( 4x + 1 )^2, dv/dx = 2cos(2x)

dy/dx = (12( 4x + 1)^2)sin(2x) + 2(( 4x + 1)^3)cos(2x)

DS
Answered by Danielle S. Maths tutor

4957 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is the best way to revise for a Maths A-level?


Integrate (x-5)/(x+1)(x-2) using partial fractions


Find the an expression for dy/dx of the function y=(4x+1)ln(3x+1) and the gradient at the point x=1.


A small stone is projected verically upwards from a point O with a speed of 19.6ms^-1. Modeeling the stone as a particle moving freely under gravity find the time for which the stone is more than 14.6m above O


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences