Solve the simultaneous equations: 4x+5y = 38 , x-y = 5

Firstly number the two equations 1 and 2 for simplicity. To solve this we want to eliminate one of the variables, x or y, so we start by looking at the equations and seeing if we can add or subtract them from each other to get rid of one of the variables. From these equations it doesnt look like we can do this immediately. What we do now is multiply equation two (x-y=5) by 5, to get our new equation three : 5x-5y =25. REMEMBER to multiply the right hand side as well... Now we see we can add equation three to eqaution one and this removes y...we are left with 9x =63. Divide by 9 to get x=7. Now plug x = 7 into one of the original equations, for simplicity use equation two. And this gives us y=2

AA
Answered by Ali A. Maths tutor

4641 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Why is the area of a triangle 1/2 * b * h?


How do you find the length of a side of a right-angled triangle given the angle and the hypotenuse?


How do you calculate arc length and sector area and why is it calculated like this? You are given sector angle 40 degrees and radius 7cm and asked to give answers to 3sf.


In a school, there is a total of 640 children. The ratio of Girls to boys is 7:9. How many boys are there in this school?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning