Solve: a) 5t + 17 = 2 b) x^3 - 25 = 103 - x^3

a) Solving for t:
We isolate our unknown t on one side, to leave the factors of t on one side and the numbers on the other:
-1st step: substract 17 from both sides --> 5t = -15
-2nd step: divide by 5 on both sides --> t = -3

b) Solving for x: We now isolate the power of x on one side:
-1st step: add x^3 on both sides --> 2*(x^3)-25=103

-2nd step: add 25 on both sides --> 2*(x^3) = 128

-3rd step: divide by two on both sides --> x^3 = 64

  • Finally to get rid of the exponent, we take the cube root on both sides of the expression --> x = 4
LC
Answered by Luis C. Maths tutor

3689 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand and simplify (x – 9)(x + 2)


Solve the simultaneous equations, 3x + y = 10 and x + y = 4.


At the supermarket, Ben buys 5 apples and 3 pears, at a total cost of £3.70. Jenny buys 6 apples and 6 pears, costing £5.40. Construct two simultaneous equations to work out the price, in pence, of apples and pears.


What is the nth term of the sequence 5, 7, 9, 11....


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning