Solve: a) 5t + 17 = 2 b) x^3 - 25 = 103 - x^3

a) Solving for t:
We isolate our unknown t on one side, to leave the factors of t on one side and the numbers on the other:
-1st step: substract 17 from both sides --> 5t = -15
-2nd step: divide by 5 on both sides --> t = -3

b) Solving for x: We now isolate the power of x on one side:
-1st step: add x^3 on both sides --> 2*(x^3)-25=103

-2nd step: add 25 on both sides --> 2*(x^3) = 128

-3rd step: divide by two on both sides --> x^3 = 64

  • Finally to get rid of the exponent, we take the cube root on both sides of the expression --> x = 4
LC
Answered by Luis C. Maths tutor

3382 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify 3(x-5)/x^2-3x-10


Solve x^2 + x -12= 0 for all values of x.


A level - Find the coordinates of the stationary point of the curve with equation : (x+y-2)^2 + e^y -1


Why maths?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences