Find the value of x in (4^5⋅x+32^2)⋅2^5=2^16⋅x

Find the value of x in (45x+322)⋅25=216x

First we transform everything into powers of 2 as all the numbers involved in this equation are multiples of 2.

||    45 = (22)5 = 22*5= 210

||    32= (25)2 = 22*5= 210
dividing over 25 on both sides and putting the powers of 2 we get
210 x + 210 = 211x ------ 216/25 = 216-5 = 211

we factorise on the left hand side of the equation

210(x+1) = 211 x --------- we divide over 210

x+1 = 2x -------- 211/210 = 211-10 = 2

Take away x on both sides -----> x =1

LC
Answered by Luis C. Maths tutor

7042 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A ball is kicked and has an instantaneous velocity of 19.6m/s at an angle of 30 degrees to the horizontal. A target lies flat on the ground in the direction the ball is kicked and lies at a distance of (98/5)*(3^1/2)m. Does the ball land on the target?


Calculate the shaded finite region between the curve and the axis for the curve: 3x^2 +11x -4 = 0


How do you differentiate a function comprised of two functions multiplied together?


Solve for 0<=θ<π, the equation sin3θ-(sqrt3)cosθ=0 (C2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences