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(2x+3)/(x-4) - (2x-8)/(2x+1) =1

(2x+3) (2x+1) = 4x^2 + 8x + 3

(2x-8) (x-4) = 2x^2 - 16x - 32

(4x^2+8x+3) - (2x^2-16x-32) = 1

2x^2 - 8x - 29 = 1

2x^2 - 8x - 30 = 0

x^2 - 4x - 15 = 0

Using the qua...

MA
Answered by Masie A. Maths tutor
1759 Views

Solve the quadratic equation x^2 - 5x - 14 = 0, using factorisation.

Using factorisation, first we would have to look at the factors that multiply to make the last term, (-14). We know that they are +/- 7 and -/+2, and +/- 14 and -/+ 1, respectively. Now we have listed the...

ME
Answered by Mram E. Maths tutor
8472 Views

List four pull factors that attract people to urban areas in Low Income Countries.

Population from low-income countries tends to migrate to high-income countries because of different factors:

-They offer a better lifestyle.

-They offer better studies also, it is where you ...

MH
Answered by Marie H. Geography tutor
8992 Views

Make a the subject of: (a+3)=(2a+7)/r

Equation: a+3 = (2a+7)/r

First, we want to rearrange the equation, so that the 'r', which is the denominator of the right hand side, multiplies with (a+3), creating r(a+3) = 2a+7. ...

JM
Answered by Jana M. Maths tutor
13624 Views

How do I simplify multiplying potencies with the same base?

If for example you have g square x g cube, all you have to do is add up the potencies and put them in the same base, so in this case it will be g5. in the case of dividing potencies all you hav...

GG
Answered by Gonzalo G. Maths tutor
2052 Views

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