(2x+3)/(x-4) - (2x-8)/(2x+1) =1

(2x+3) (2x+1) = 4x^2 + 8x + 3

(2x-8) (x-4) = 2x^2 - 16x - 32

(4x^2+8x+3) - (2x^2-16x-32) = 1

2x^2 - 8x - 29 = 1

2x^2 - 8x - 30 = 0

x^2 - 4x - 15 = 0

Using the quadratic formula;

x = 6.36 or x= -2.36 to 2dp

MA
Answered by Masie A. Maths tutor

1816 Views

See similar Maths 13 Plus tutors

Related Maths 13 Plus answers

All answers ▸

Find 16% of £435


How do I calculate the 100th term of the sequence 15, 8, 1, -6...


Given a=2, b=-5, c=0.5, d=-20 ... find abc, and 2d+10c


Find all solutions to the equation: 2x^2+3x-27=0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning