"Solve cos(3x +20) = 0.6 for 0 < x < 360" - why are there more than one solution, and how do I find all of them?

The important part of this question is to really understand what the cosine function looks like, many students will use their calculators to find arccos(0.6) = 53.13 degrees, but not find the other solutions to the problem, eg: arcos (0.6) = 53.13, 306.37, 413.13 and so on.

Many students will therefore arrive at 53.13 = 3x+20 as the only solution and therefore 33.13 = 3x and finally x = 11.04 as the only solution, when in fact there are many.

Therefore it is always useful to draw a graph of the cosine function and demonstrate why there are multilpe solutions. We then need to know how many of the solutions will fall within the condition 0 < x <360, as a trick, we consider 0 < 3x < 1080 and then 20 < 3x + 20 < 1100. From this, we infer that any value of arccos(0.6) which falls between 20 and 1100 will be a solution to the problem.

Eg: cos(773.13) = 0.6     therefore letting 773.13 = 3x+20 we solve for x and get x = 251.04.

MF
Answered by Martyn F. Maths tutor

6123 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Consider the function f (x) = (2/3) x^3 + bx^2 + 2x + 3, where b is some undetermined coefficient: (a) find f'(x) and f''(x) and (b) if you know that f(x) has a stationary point at x = 2, use this information to find b.


g(x) = x/(x+3) + 3(2x+1)/(x^2 +x - 6) a)Show that g(x) =(x+1)/(x-2), x>3 b)Find the range of g c)Find the exact value of a for which g(a)=g^(-1)(a).


Use the substitution u = 2^x to find the exact value of ⌠(2^x)/(2^x +1)^2 dx between 1 and 0.


solve 2cos^2(x) - cos(x) = 0 on the interval 0<=x < 180


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning