Find the gradient of a straight line with the points P(5,3) and Q(8,12)

First we draw a picture, to visually see what the question is asking. A simple set of coordinate-axes and notches so we can accurately put our point P and Q, though being accurate isn't important it will give a good idea of what kind of numbers we are looking for. Now the gradient represents 'for every step x along, we go y steps up' so we want to divide dy (the differnce in the y values) by dx (the differnce in the x values). That is to say dy/dx=(12-3)/(8-5)=9/3=3. This is the answer.

AG
Answered by Alexander G. Maths tutor

3446 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate 3x^2 + 4x - 7


How would I find the approximate area enclosed by the expression e^x*sin(x)*x^3 on an infinite scale?


Imagine a sector of a circle called AOB. With center O and radius rcm. The angle AOB is R in radians. The area of the sector is 11cm². Given the perimeter of the sector is 4 time the length of the arc AB. Find r.


show that y = (kx^2-1)/(kx^2+1) has exactly one stationary point when k is non-zero.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences