The line AB has equation 5x+3y+3=0. It is parallel to a line with equation y=mx+7. What is m?
If the lines are parallel then when the line AB is given in the form y=mx+c then the gradient m of AB is equal to that of the other line. Rearranging the equation for line AB gives y=-(5/3)x-1 so m=-(5/3)
MT
Related Maths A Level answers
All answers ▸How do you sketch the curve y=(x^2 - 4)(x+3), marking on turning points and values at which it crosses the x axis
A curve is described by the equation x^3 - 4y^2 = 12xy. a) Find the points on the curve where x = -8. b) Find the gradient at these points.
Consider the function F(x)=17(x^4)+13(x^3)+12(x^2)+7x+2. A) differentiate F(x) B)What is the gradient at the point (2,440)
Using the substitution x = 2cosu, find the integral of dx/((x^2)(4-x^2)^1/2), evaluated between x=1 and x=sqrt(2).