A graph is sketched with the equation x^2+4x-5. Find the minimum point of this graph.

Okay so the first thing we can identify is that it is a quadratic, hence the x2 at the beginning. From this we can now start to answer the question. To calculate the minimum point we must "complete the square"; this method involves getting the x into a squared bracket, so from "x2" to "(x+ or -...)2 " whilst considering the number which is not a coefficient (the number made when the squared racket is multiplied out). The first thing we do is halve the x coefficient (so the 4x). In order to 'recreate' the 4x you would have to have two lots of the new coefficient, 2x. If this is put into a squared bracket like so: (x+2)2, when multiplied out you have x2+4x (which is what you want) +4, which is what you want to change. The target equation is in the question, so in order for x2+4x +4 to become x2+4x -5, you have to subtract 9. As x2+4x+4 is equal to (x+2)2, the equation x2+4x-5 is equal to (x+2)2-9. The minimum point is (-x coefficient, Number outside) so it would be (-2, -9).

HS
Answered by Harry S. Maths tutor

4905 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I complete the square


y is directly proportional to (d+2)^2, when d=5, y=147. d^2 is inversely proportional to x^2, when d=2, x=3. Find an equation for y in terms of x


The point P has coordinates (3, 4) The point Q has coordinates (a, b) A line perpendicular to PQ is given by the equation 3x + 2y = 7 Find an expression for b in terms of a


Solve the quadratic equation: x^2 - 2x - 15 = 0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning