The equation 2x^2 + 2kx + (k + 2) = 0, where k is a constant, has two distinct real roots. Show that k satisfies k^2 – 2k – 4 > 0

Two distinct real roots means that we can use b^2-4ac>0 relationship for any ax^2+bx+c equation. Apply the above gives, 4k^2 - 42(k+2)>0 Simplifying gives, k^2 - 2k -4 >0

AT
Answered by Andreas T. Maths tutor

11738 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

what is the difference between remainder and factor theorem?


Rationalise the denominator of 25/sqrt(5)


given that y = 1 when x = π, find y in terms of x for the differential equation, dy/dx = xycos(x)


Two lines have equations r = (1,4,1)+s(-1,2,2) and r = (2,8,2)+t(1,3,5). Show that these lines are skew.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning