How would I differentiate a function such as f(x)=x^3(e^(2x))?

Here, f(x)=x3e2x is a function consisting of two functions multiplied together, so we need to use the product rule. The product rule is as follows: where f(x)=u(x)v(x), f'(x)=u(x)v'(x)+u'(x)v(x). The first step involves identifying the two functions that are multiplied together, and representing them by u and v. So, let u(x)=x3 and v(x)=e2x. Now, we must find u'(x) and v'(x). u'(x)=3x2 (from Core 1: multiply by the power, then subtract 1 from the power) and v'(x)=2e2x  (from using the chain rule). Then, substitute u(x), v(x), u'(x) and v'(x) into our product rule formula, giving f'(x)=x. 2e2x + 3x.e2x     If you wish to simplify this, you can do so by taking out a common factor of x2e2x from each term: f'(x)=x2e2x(2x+3)

LB
Answered by Lauren B. Maths tutor

3541 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A circle with centre C has equation x^2+8x+y^2-12y=12. The points P and Q lie on the circle. The origin is the midpoint of the chord PQ. Show that PQ has length nsqrt(3) , where n is an integer.


How do you show that (x+2) is a factor of f(x) = x^3 - 19x - 30, and then factorise f(x) completely?


How do I find the equation of a tangent to a given point on a curve?


Find the centre coordinates, and radius of the circle with equation: x^2 + y^2 +6x -8y = 24


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning