A straight line passes through the points (-2, 4) and (1, 10). What is (a) the gradient of the line, (b) the y-intercept of the line and (c) the equation of the line?

(a) Gradient (m) = (y2-y1)/(x2-x1) = (10-4)/(1-(-2)) = 6/3 = 2

(b) General equation of a straight line: y = mx + c    (c = y-intercept)

For our straight line: y = 2x + c

Test points: 4 = 2(-2) + c ---> c = 8

(c) General equation of our straight line: y = 2x + 8 

SB
Answered by Samuel B. Maths tutor

14397 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve for x in the following equation using the quadratic formula, completing the square and factoring method: 2x^2-x-1=0


What is the nth term of the sequence 5, 7, 9, 11....


Differentiate y=3x^4 with respect to x


Mike, Sam and James play football. Mike scores 8 more goals than James. Sam scores 5 more goals than Mike. Altogether they score 72 goals. How many did Sam score?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning