How do you find the gradient of a straight line?

The gradient of a straight line is the number before the x if it is in the form y=mx+c. So for y=6x+2 the gradient is 6. If the y has a factor, like 2y=6x+2, then you have to divide everything by the factor to get just y=, so the equation would be y=3x+1 and so the gradient would be 3. If you have been given a diagram instead of the equation, you'll need to work out the change in y-coordinate divided by the change in x-coordinate. So to do this, you pick any two points on the graph and work out the difference between the two y-coordinates and the difference between the two x-coordinates and then divide your answer for y-coordinates by your answer for x-coordinates. Example: points on line (3,2) and (6,10). Change in y is 10-2=8, change in x is 6-3=3. Gradient is 8/3.

HW
Answered by Hebe W. Maths tutor

25569 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following to find x. x^2 +3x -10 =0


Show that (x + 1)(x + 2)(x + 3) can be written in the form ax3 + bx2 + cx + d where a, b, c and d are positive integers.


Rearrange the following to make m the subject. 4(m – 2) = t (5m + 3)


Make x the subject of 3y + 2x = 6y - x/2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning