If y=3x^3e^x; find dy/dx?

Using the product rule we know that dy/dx = uv' + vu' where u = 3x^3; v = e^x. e^x differentiates to itself multiplied by any number in front of the x. u' = 9x^2; v' = e^x. Therefore dy/dx = 3x^3e^x + 9x^2e^x. This could be simplified further if the question asks for the answer in its simplest form. 

AG
Answered by Aimee G. Maths tutor

5128 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Express 9^3x + 1 in the form3^y ?


Differentiate cos(2x)/(x) with respect to x


A curve is defined for x>0 as y = 9 - 6x^2 - 12x^4 . a) Find dy/dx. b) Hence find the coordinates of any stationary points on the curve and classify them.


A curve has equation -2x^3 - x^2 + 20x . The curve has a stationary point at the point M where x = −2. Find the x-coordinate of the other stationary point of the curve.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences