If y=3x^3e^x; find dy/dx?
Using the product rule we know that dy/dx = uv' + vu' where u = 3x^3; v = e^x. e^x differentiates to itself multiplied by any number in front of the x. u' = 9x^2; v' = e^x. Therefore dy/dx = 3x^3e^x + 9x^2e^x. This could be simplified further if the question asks for the answer in its simplest form.
AG
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