How do you integrate y = 4x^3 - 5/x^2?

First we should look at the formula for integrating xⁿ. The integral is (xⁿ⁺¹ / n+1) + C.

Let's break down our equation into two parts. 

1. The integral of 4x³ = 4(x³⁺¹ / 3+1) = 4(x⁴ / 4) = x⁴

2. The integral of -5/x² = -5(x^-2+1 / -2+1) = -5(x^-1 / -1) = 5(x^-1) = 5/x

So the integral of y = x⁴  + 5/x + C