Solve these simultaneous equations: 2x+y-5=0 and x^2-y^2=3

To solve this problem, you need to: rearrange the first equation (1) to express y in terms of x to obtain equation (3). Then, substitute this new equation into the quadratic one (the second equation from the problem (2)). Using the formula, expand the brackets (be careful with the negative sign!) and obtain the following quadratic equation: 3x²-20x+28=0. Find the discriminant (D=64), and using the formula find values for x₁ and x_2. After, using (3), find values for y₁ and y_2. x₁=14/3, y₁= - 13/3 and x₂=2 and y₂=1

full, step-by-step solution will be demonstrated during the lesson