How do you solve the simultaneous equations 3x + 4y = 5 and 2x – 3y = 9

We label each equation

3x + 4y = 5 (1)

2x – 3y = 9 (2)

We now want to get rid of one of the variables (x or y). Lets get rid of x:

We need (1) and (2) to have the same number of x's so we multiple (1) by 2 and (2) by 3 so they both have 6 x's

6x + 8y = 10 (1)*2

6x - 9y = 27 (2)*3

Now to get rid of the x's we take one of the equations from the other. It is easier to do (2)*3 -(1)*2

  6x - 9y = 27 (2)*3

- 6x + 8y = 10 (1)*2

                                   

     -17y = 17 

If we devide this equation by -17 we get

y = -1

We can plug this value of y into (1) to get

3x -4 = 5

add 4 to both sides of the equation

3x = 9

Divide by 3

x = 3

Now to check put x and y into (2)

6 - (-3) = 9 

As this is true, we have the solution

x = 3, y = -1

SS
Answered by Sahiti S. Maths tutor

40011 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A group of 55 students were asked if they had a cat or a dog. 11 were known to own both, 18 said they owned only a dog, and 34 said they owned at least a cat. Give the probability that a student has neither as a fraction in its simplest form.


A rectangle has sides of length 4x cm and (x+3)cm and has an area less than 112 cm^2, find the set of values x can take


(2x+3)/(x-4) - (2x-8)/(2x+1) = 1 Solve for x


What is the difference between LCM and HCF?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences