Given that sin(x)^2 + cos(x)^2 = 1, show that sec(x)^2 - tan(x)^2 = 1 (2 marks). Hence solve for x: tan(x)^2 + cos(x) = 1, x ≠ (2n + 1)π and -2π < x =< 2π(3 marks)

sin(x)2 + cos(x)2 = 1

Dividing by cos(x)2 gives:

tan(x)2 + 1 = sec(x)2 

Which rearranges as:

sec(x)2 - tan(x)2 = 1 as required.

tan(x)2 + cos(x)2 = 1

sec(x)2 - 1 + cos(x)2 = 1

sec(x)2 + cos(x)2 = 2

1 + cos(x)4 = 2cos(x)2

(cos(x)2 -1)2 = 0

cos(x)2 = 1

cos(x) = 1

x = 0, 2π

AR
Answered by Alistair R. Maths tutor

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