(2x+3)/(x-4) - (2x-8)/(2x+1) = 1 Solve for x

Multiply out the denominator, take care to multiply both sides of the equation:

(2x+3)(2x+1) - (2x-8)(x-4) = (2x+1)(x-4)

Expand the brackets, pay attention the the signs when multiplying, expecially the negative between the two sets of brackets on the left hand side.

4x2+2x+6x+3 - (2x2-8x-8x+32)=2x2-7x-4

4x2+2x+6x+3-2x2+8x+8x-32=2x2-7x-4

Group like terms on each side of the equation.

2x2+24x-29=2x2-7x-4

Bring all the terms to one side to leave a quadratic equation equal to 0. Remember to change the sign as you bring a term from one side to the other. 

31x-25 = 0

Rearrange for x

x= 25/31 (=0.81)

Answered by Lucy M. Maths tutor

2377 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Prove that the square of an odd number is always 1 more than a multiple of 4.


How would one multiply out brackets?


How to solve problems with discount applied twice in the same product?


Solve 7(k-3)=3k-5


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy