How would you show that a vector is normal to a plane in 3D space?

There are 2 main methods for finding a normal vector.

  1. If you know two vectors that lie in the plane e.g. (a,b,c) and (d,e,f), we can find a normal vector by calculating the vector/cross product of (a,b,c) and (d,e,f). This works because the vector product produces a new vector perpendicular to both your starting vectors, so it must be at right angles to the plane.

  2. If on the other hand you know the Cartesian equation of a plane, which looks like (ax)+(by)+(cz)=0, then the vector (a,b,c) is a normal vector!

FK
Answered by Fionn K. Maths tutor

28976 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The curve C has the equation (x^2)+4xy-8(y^2)+27=0. Find dy/dx in terms of x and y.


How do you show that two lines do, or do not intersect?


X=4x^2 + 5x^7 - sin(3x) find dy/dx


Use Implicit Differentiation to find dy/dx of the following equation: 3(x)^2 + 8xy + 5(y)^2 = 4


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning