Solve for -pi < x < pi: tanx = 4cotx + 3

tanx = 4cotx + 3  - Multiply through by tan to form a quadratic. tan^2x = 4 + 3tanx - Simplify by allowing y to equal tanx. y^2 = 4 + 3y - Rearange to standard quadratic form. y^2 - 3y -4 = 0 - Factorise. (y - 4)(y + 1) = 0 Therefore y = 4 and y = -1 Substitute y=tanx to solve for x: y = 4 tanx = 4 x = tan-14 x= 1.326 (3d.p.) tanx = -1 x = tan-1 -1 x = -pi/4

ZL
Answered by Zak L. Maths tutor

6199 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Figure 1 shows a sector AOB of a circle with centre O and radius r cm. The angle AOB is θ radians. The area of the sector AOB is 11 cm2 Given that the perimeter of the sector is 4 times the length of the arc AB, find the exact value of r.


Derive the quadratic formula. From it, write down the determinant and explain, how is it related to the roots of a quadratic equation.


Use integration to find the exact value of [integral of] (9-cos^2(4x)) dx


Solve the equation 8x^6 + 7x^3 -1 = 0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning