Find the indefinite integral of Ln(x)
This question requires integration by parts, using the formula:
Integral(u dv) = u v - integral(v du)
This is applied to find the integral of Ln(x) by writing Ln(x) as 1 * Ln(x), u is then Ln(x) and dv is 1.
Differentiating u=Ln(x) gives you du=1/x. Integrating dv=1 gives you v=x.
Then substituting into formula gives you: Integral(Ln(x)) = xLn(x) - Integral(x*1/x) = xLn(x) - Integral(1)
Therefore Intergral(Ln(x)) = xLn(x) - x + C, Where C is the integration constant
TD
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