Find the gradient of the curve y=sin(x^2) + e^(x) at the point x= sqrt(pi)
y=sin(x2) + ex Firstly we need to differentiate. dy/dx = 2xcos(x2) + ex using the chain rule Notice the gradient at x = sqrt(pi) is found when we sub x into dy/dx Hence dy/dx = 2*sqrt(pi)cos( sqrt(pi)2) + esqrt(pi) = esqrt(pi) - 2sqrt(pi)
JR
Related Maths A Level answers
All answers ▸How do I rewrite 2 cos x + 4 sin x as one sin function?
How can I improve my score?
use the substitution u=2+ln(x) to show that int(e,1(ln(x)/x(2+ln(x)^2))dx)=p+ln(q) , where p and q are rational numbers.
How can I get better at Mathematics? I am struggling with confidence and achieving low grades.