Find the gradient of the curve y=sin(x^2) + e^(x) at the point x= sqrt(pi)

y=sin(x²) + e^x Firstly we need to differentiate. dy/dx = 2xcos(x²) + e^x using the chain rule Notice the gradient at x = sqrt(pi) is found when we sub x into dy/dx Hence dy/dx = 2*sqrt(pi)cos( sqrt(pi)²) + e^sqrt(pi) = e^sqrt(pi) - 2sqrt(pi)