Find the gradient of the curve y=sin(x^2) + e^(x) at the point x= sqrt(pi)
y=sin(x2) + ex Firstly we need to differentiate. dy/dx = 2xcos(x2) + ex using the chain rule Notice the gradient at x = sqrt(pi) is found when we sub x into dy/dx Hence dy/dx = 2*sqrt(pi)cos( sqrt(pi)2) + esqrt(pi) = esqrt(pi) - 2sqrt(pi)
JR
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