f(x) = x^3 + 3x^2 + 5. Find f'(x) and f''(x).
With differentitaion you multiply the fatcor it's raised by and minus one from the order
e.g. y = x^n so y' = nx^(n-1)
So f'(x) = 3x^2 + 6x and f''(x) = 6x + 6
NS
With differentitaion you multiply the fatcor it's raised by and minus one from the order
e.g. y = x^n so y' = nx^(n-1)
So f'(x) = 3x^2 + 6x and f''(x) = 6x + 6
