Find the equation of the straight line joining points (-1, -4) and (2, 5)

  1. Draw sketch of line 2. Find gradient using m=(y- y1)/(x- x1)= 5--4/2--1=9-3=3 3. Choose one of the points and call it (a,b). I'll pick (2,5) because there's no negaitves. 4. Sub into equation y-b=m(x-a)   y-5= 3(x-2) 5. Simplify  y - 5 = 3x - 6    y = 3x - 1
BM
Answered by Ben M. Maths tutor

8668 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the Simultaneous equations '2x-3y=24' and '6x+2y=-5'


Solve the simultaneous equations x + y = 2 and x^2 + 2y = 12


n is an integer greater than 1. Prove algebraically that n^2 – 2 – (n – 2)^2 is always an even number.


Solve x^2+6x+5=0 for x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning