Find the equation of the straight line joining points (-1, -4) and (2, 5)

  1. Draw sketch of line 2. Find gradient using m=(y- y1)/(x- x1)= 5--4/2--1=9-3=3 3. Choose one of the points and call it (a,b). I'll pick (2,5) because there's no negaitves. 4. Sub into equation y-b=m(x-a)   y-5= 3(x-2) 5. Simplify  y - 5 = 3x - 6    y = 3x - 1
BM
Answered by Ben M. Maths tutor

8430 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify fully (x^2 + 3x)/(4x + 12) ​


Solve the Simultaneous equations 4x - y = 8 and x + y = 12


what is the median, mode and mean?


Show that (x+2)(x+3)(x+5) can be written in the form ax^3 + bx^2 + cx +d, where a,b, c and d are positive integers


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning