Find the equation of the straight line joining points (-1, -4) and (2, 5)

  1. Draw sketch of line 2. Find gradient using m=(y- y1)/(x- x1)= 5--4/2--1=9-3=3 3. Choose one of the points and call it (a,b). I'll pick (2,5) because there's no negaitves. 4. Sub into equation y-b=m(x-a)   y-5= 3(x-2) 5. Simplify  y - 5 = 3x - 6    y = 3x - 1
BM
Answered by Ben M. Maths tutor

8482 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Write 36 as a product of its prime factors


If an equation of a line is y=2x+4 and it crosses the x axis at point R, what is the value of x?


Draw the graph of y=x^2-4x-21


Here are the first four terms of a quadratic sequence: 11 26 45 68. Work out an expression for the nth term.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning