4x-y=3 and 3x-2y=1. Solve these simultaneous equations to find values for x and y.
Equation 1: 4x-y=3 Equation 2: 3x-2y=1
We have to find a common multiple between 4 and 3 so that both equations have the same first value. This means that we can get rid of the x by subtracting the second equation from the first. This will leave us with a simple linear equation with which we can solve to find y and then go on to find x. The lowest common denominator between 4 and 3 is 12.
3(4x-y)=3x3 -> 12x-3y=9 (Eq. 1)
4(3x-2y)=4x1 -> 12x-8y=4 (Eq. 2)
Eq. 1 - Eq.2 = 12x-12x-3y--8y=9-4 -> 5y=5
hence y=1 and now we have to input the y value into the first (or second) equation to find x
4x-1=3 -> 4x=4 -> x=1
So x=1 and y=1
JH
Related Maths GCSE answers
All answers ▸A stone is thrown upwards with a speed of v metres per second. The stone reaches a maximum height of h metres. h is directly proportional to v^2. When the stone is thrown at 10m/s, max height is 5m. Work out the maximum height reached when v = 24.
Find the value of 125^(2/3)
A right-angled triangle has an angle of 30 degrees and its hypotenuse has a length of 9cm. Find the length of either of the triangle's other two sides.
Solve by factorisation. 2x(^2)+5x-12=0