What is the y-coordinate minimum point of y = 3x^2 + x - 4

if y=3x^2 + x -4 

then 

dy/dx = 6x + 1

setting this equal to zero gives

6x + 1 = 0

so then

x = -1/6

putting this x value back into the original equation gives

y = -49/12

MW

Related Maths A Level answers

All answers ▸

Differentiate the function f(x) = x^2 * e^2x with respect to x


Express 6cos(2x) + sin(x) in terms of sin(x), hence solve the equation 6cos(2x) + sin(x) = 0 for 0<x<360


Write 9sin(x) + 12 cos(x) in the form Rsin(x+y) and hence solve 9sin(x) + 12 cos(x) = 3


Find dy/dx when y = (3x-1)^10