What is the y-coordinate minimum point of y = 3x^2 + x - 4
if y=3x^2 + x -4
then
dy/dx = 6x + 1
setting this equal to zero gives
6x + 1 = 0
so then
x = -1/6
putting this x value back into the original equation gives
y = -49/12
MW
Related Maths A Level answers
All answers ▸Find the coordinates of the minimum point on the curve: y = x^2 - x - 2
Integrate with respect to x ) dy/dx= 6x^5
Solve for 0<=θ<π, the equation sin3θ-(sqrt3)cosθ=0 (C2)
Solve the equation d/dx((x^3 + 3x^2)ln(x)) = 2x^2 + 5x, leaving your answer as an exact value of x. [6 marks]