What is the y-coordinate minimum point of y = 3x^2 + x - 4
if y=3x^2 + x -4
then
dy/dx = 6x + 1
setting this equal to zero gives
6x + 1 = 0
so then
x = -1/6
putting this x value back into the original equation gives
y = -49/12
MW
if y=3x^2 + x -4
then
dy/dx = 6x + 1
setting this equal to zero gives
6x + 1 = 0
so then
x = -1/6
putting this x value back into the original equation gives
y = -49/12