Solve the simultaneous equations. 3x + 5y = 1 , 2x - 3y = 7

3x + 5y = 1   (eq 1)
2x - 3y = 7    (eq 2)

Step 1 -  2* (eq 1) 

6x + 10y = 2  (eq 3)

Step 2 - 3* (eq 2)

6x - 9y = 21  (eq 4)

Step 3  -  eq 4 - eq 3 to cancel the x

-19y = 19 

Therefore, y = -1  (eq 5)

Step 4 - sub (eq 5) back into (eq 1)

3x + 5(-1) = 1

3x - 5 = 1

3x = 6 and therefore x = 2 (eq 6)

Step 5 - Sub (eq 5) and (eq 6) into (eq 2) to check answer. 

AL
Answered by Ann L. Maths tutor

14281 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Express x^2+8x+15 in the form (x+a)^2-b


L1: y=3x-2 & L2: 3y-9x+5=0, show these two lines are parallel


Factorise x^2 + 2x - 3


express 63 as a product of its prime factors


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning