Find the normal to the curve y = x^2 at x = 5.
Differentiate the original equation (y = x^2) to find the gradient (m) of the line which is a tangent to the curve.
Dy/dx = 2x
Therefore m = 2
Calculate the negative reciprocal (m2) which will give the gradient of the normal.
m2 = -0.5
Using the equation y=mx+c find the equation of the normal.
When x=5, y=25.
25=(-0.5)(5) + c
c=27.5
y=-0.5x+27.5
AS
Related Maths A Level answers
All answers ▸Find the exact value of dy/dx at (-2,4) of the curve C: 4x^2 -y^2 + 6xy + 2^y = 0
Express 2cos(x) + 5sin(x) in the form Rsin(x + a) where 0<a<90
Find the stationary points on y = x^3 + 3x^2 + 4 and identify whether these are maximum or minimum points.
If x=-2,1,2 and the y intercept is y=-8 for y=ax^3+bx^2+cx+d, what is a, b, c and d