Solve for x, 5sin(x) - 3cos(x) = 2 , in the interval 0<x<2pi

5sin(x)-3cos(x)=2

Express in the form Rsin(x-@) = Rsin(x)cos@ - Rcos(x)sin@

Rcos@ =5

Rsin@ = 3    

tan@ = 3/5           @=tan-1(3/5)= 0.540

R = sqrt(52 +32 )= sqrt(34)

sqrt(34)sin(x-0.540) = 2

sin(x - 0.540) = 0.343

Let Y = x-0.540

sinY = 0.343         in the interval -0.540 < Y < 5.743

Y = sin-1 (0.343)=0.350

Using CAST diagrams, we obtain 0.350 and pi-0.350 in this interval

Y = 0.350, 2.791

x = 0.350 + 0.540, 2.791 + 0.540

x = 0.890, 3.331

SM
Answered by Stefan M. Maths tutor

4233 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The equation 2x^2 + 2kx + (k + 2) = 0, where k is a constant, has two distinct real roots. Show that k satisfies k^2 – 2k – 4 > 0


Points P and Q are situated at coordinates (5,2) and (-7,8) respectively. Find a) The coordinates of the midpoint M of the line PQ [2 marks] b) The equation of the normal of the line PQ passing through the midpoint M [3 marks]


Show that the volume of the solid formed by the curve y=cos(x/2), as it is rotated 360° around the x-axis between x= π/4 and x=3π/4, is of the form π^2/a. Find the constant a.


What is the equation of the normal line to the curve y = 3x^3 - 6x^2 at the point (1, 4)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences