The points A and B have coordinates (3, 4) and (7, 6) respectively. The straight line l passes through A and is perpendicular to AB. Find an equation for l, giving your answer in the form ax + by + c = 0, where a, b and c are integers.

For the line passing through A and B: m = (y2-y1)/(x2-x1) = (-6-4)/(7-3) = -5/2

For the perpendicular line: m = -1/(-5/2) = 2/5 

y - y1 = m*(x - x1)  >>  y - 4 = (2/5)*(x - 3)  >>  5y - 20 = 2x - 6  >>  2x - 5y + 14 = 0

DA

Related Maths A Level answers

All answers ▸

I know how to integrate, but I still never see any real world example of it, so it is difficult to understand. Why is it useful?


complete the square of x^2 + 2x - 6


Integral between 0 and pi/2 of cos(x)sin^2(x)


Differentiate with respect to x: x*cos(x)