A compound being analysed has the percentage composition by mass Ca = 13.9%, W = 63.9%, O = 22.2%. Calculate the empirical formula of this compound

Using rows to represent mathematical operations and a column for each compound we can draw ourselves a table:

                             Ca       W      O
%                         13.9    63.9   22.2
Atomic Mass (Ar) 40       184    16
% / (Ar)                 0.348  0.347 1.43
Ratio                    1    :     1   :   4

This produces the empirical formula Ca1W1Oor more commonly written CaWO4. We retrieve the atomic mass from our periodic table and then divide teh percentage by mass given in the question for each element by its atomic mass. We then take the smallest of these numbers and divide all the other % / (Ar) by it to produce a ratio, it doesn't matter if they aren't exact, they just have to be close to a whole number. This ratio is the ratio of elements in the empirical formula.

HD
Answered by Haydn D. Chemistry tutor

5539 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

A metal oxide has a relative formula mass (Mr ) of 81. The formula of this metal oxide is MO. Given that the relative atomic mass (Ar ) of oxygen is 16, what is the metal in the metal oxide?


Explain, in terms of sub-atomic particles, why the mass number of a magnesium atom is 24.


How would you preform the flame test to identify the presence of Sodium in a solution? (3Marks)


Name and explain the process in which crude oil is separated into fractions. (5 marks)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning