3. The point P lies on the curve with equation y=ln(x/3) The x-coordinate of P is 3. Find an equation of the normal to the curve at the point P in the form y = ax + b, where a and b are constants.
P- (3,0) y=ln(x/3) u=x/3 y=ln(u) du = 1/3 dy = 1/u = 3 dx du dy= du x dy dx dx du = 1/3 x 3 = 1 gradient at normal = -1 equation at normal = y = m(x) + c 0 = -3 + c 3 = c Answer: equation at normal = y = -x + 3
KB
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