The random variable J has a Poisson distribution with mean 4. Find P(J>2)

P(J>2) = P(J=0)+P(J=1)     [split it up]

P(X=t)= (V^t)/t!*e^V       where V=4 in this case  [use the formula]

P(J>2) = 4^0/0!*e^4 + 4^1/1!*e^4

          =1/e^4 + 4/e^4  =  5e^-4  which is roughly  0.0916

NC
Answered by Nathan C. Maths tutor

3807 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the gradient at the point (0, ln 2) on the curve with equation e^2y = 5 − e^−x


Solve the inequality x^2 - 9 > 0


How do you know how many roots a quadratic equation has?


Find dy/dx in terms of t for the curve given by the parametric equations x = tan(t) , y = sec(t) for -pi/2<t<pi/2.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences