The random variable J has a Poisson distribution with mean 4. Find P(J>2)

P(J>2) = P(J=0)+P(J=1)     [split it up]

P(X=t)= (V^t)/t!*e^V       where V=4 in this case  [use the formula]

P(J>2) = 4^0/0!*e^4 + 4^1/1!*e^4

          =1/e^4 + 4/e^4  =  5e^-4  which is roughly  0.0916

NC
Answered by Nathan C. Maths tutor

4053 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve the following definite integral: f(x)=3e^(2x+1) for the limits a=0 and b=1, leaving your answer in exact form.


A block of mass 5 kg is being pushed over level ground by rod at 60 degrees to horizontal with force 40 N with acc. 1.5 what is the frictional force of the surface and draw a diagram with the forces acting on the block


Find the derivative with respect to x and the x-coordinate of the stationary point of: y=(4x^2+1)^5


f(x) = (4x + 1)/(x - 2) with x > 2. Find a value for 'x' such that f'(x) (first derivative of f(x) with respect to x) is equal to -1.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning