The random variable J has a Poisson distribution with mean 4. Find P(J>2)

P(J>2) = P(J=0)+P(J=1)     [split it up]

P(X=t)= (V^t)/t!*e^V       where V=4 in this case  [use the formula]

P(J>2) = 4^0/0!*e^4 + 4^1/1!*e^4

          =1/e^4 + 4/e^4  =  5e^-4  which is roughly  0.0916

NC
Answered by Nathan C. Maths tutor

4527 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I find the inverse of a function?


Integrate x/((1-x^2)^0.5) with respect to x


Use the substitution u=1+e^x to find the Integral of e^(3x) / (1 + e^x)


The polynomial f(x) is define by f(x) = 3x^3 + 2x^2 - 8x + 4. Evaluate f(2).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning