What is the area bound by the x-axis, the lines x=1 and x=3 and the curve y=3x^(2)-1/x ? Answer in exact form.

Integrate, y= 3x-1/x

 1{3x- 1/x dx = [x-lnx]31= (3-ln3)-(1-ln1) = 3-ln3-1+0= 2-ln3

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Answered by Escher L. Maths tutor

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