What is the area bound by the x-axis, the lines x=1 and x=3 and the curve y=3x^(2)-1/x ? Answer in exact form.
Integrate, y= 3x2 -1/x
1{3 3x2 - 1/x dx = [x-lnx]31= (3-ln3)-(1-ln1) = 3-ln3-1+0= 2-ln3
Integrate, y= 3x2 -1/x
1{3 3x2 - 1/x dx = [x-lnx]31= (3-ln3)-(1-ln1) = 3-ln3-1+0= 2-ln3
