Sketch the graph y=Ax^2 where A is a constant

If A is negative, then it would be like an upsidedown 'bucket' where the only intersection is in the origin.

If A is positive, then it would be similar but flipped on the x-axis. So it would look like a 'bucket' sitting on the origin.

RI
Answered by Rafi I. Maths tutor

4964 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve 8(4^x ) – 9(2^x ) + 1 = 0


Express 4sin(x)+6cos(x) in terms of Rsin(x+a) where R and a are constants to be determined (a should be given in rad).


differentiate y=8x^3 - 4*x^(1/2) + (3x^2 + 2)/x


Integrate x((x^2)+2) dx


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning