differentiate 4x^3 + 3x^2 -5x +1

when differentiating, we multiply the power by the coefficient and then take the power away by 1 so : y= 4x^3 + 3x^2 -5x +1 then 4 x 3= 12 and 3-1 = 2 meaning the solution is 12x^2. 2 x 3 = 6 and 2-1 = 1 giving a solution of 6x. 1x.-5= -5 amd 1-1= 0 so the x value dissapears as x^0 = 1 and finally the 1 does not have a variable so it can't be differentiated so it is excluded. so dy/dx= 12x^2 + 6x -5 

JR
Answered by James R. Maths tutor

4057 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do i solve differential equations?


Where do the graphs of y=3x-2 and y=x^2+4x-8 meet?


Why is my answer incorrect?


Differentiante y = arctan(c)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences