A curve C has the equation x^3 +x^2 -10x +8. Find the points at which C crosses the x axis.

Factorise: (x-2)(x+4)(x-1)

Set equal to 0: (x-2)(x+4)(x-1) = 0

Points are (2,0) (-4,0) (1,0)

WF
Answered by William F. Maths tutor

3483 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Sketch the graph of f(x) = sin(x). On the same set of axes, draw the graph of f(x)+2, f(2x) and f(-x). By observing your graphs of f(x) and f(x), if f(a)=1, what is the value of f(-a)?


Find the derivative of the function y=3x^2e^(2x)sin(x).


Find INT{2,1}{x^4 + 3x^2 + 2}


For a given function F(x), what does the graph of the function F(x+2) look like in comparrison to F(x)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning