A curve C has the equation x^3 +x^2 -10x +8. Find the points at which C crosses the x axis.

Factorise: (x-2)(x+4)(x-1)

Set equal to 0: (x-2)(x+4)(x-1) = 0

Points are (2,0) (-4,0) (1,0)

WF
Answered by William F. Maths tutor

3546 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the coordinates of the stationary points y=x^4-8x^2+3


f(x) = sinx. Using differentiation from first principles find the exact value of f' (π/6).


Consider the functions f and g where f (x) = 3x − 5 and g (x) = x − 2 . (a) Find the inverse function, f^−1 . (b) Given that g^−1(x) = x + 2 , find (g^−1 o f )(x) . (c) Given also that (f^−1 o g)(x) = (x + 3)/3 , solve (f^−1 o g)(x) = (g^−1 o f)(x)


Simplify fully: (5 +√7)/ (2+√7)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning