find the integral of f'(x)=2x+5

f'(x)=2x+5

note that f'(x)=nx^n-1

so 2x is originally x² as this is 2x^2-1

and 5 is originally 5x^1-1

 f(x)= x²+5x+c

the c is a constant which means it's any real number without an x to it as 0 is  0(any number)x^0-1 which is 0.