find the integral of f'(x)=2x+5
f'(x)=2x+5
note that f'(x)=nxn-1
so 2x is originally x2 as this is 2x2-1
and 5 is originally 5x1-1
f(x)= x2+5x+c
the c is a constant which means it's any real number without an x to it as 0 is 0(any number)x0-1 which is 0.
ZS
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