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Differentiate 2x^3+23x^2+3x+5 and find the values of x for which the function f(x) is at either at a maximum or minimum point. (Don't need to specify which is which)

f(x)=2x³+23x²+3x+5

f'(x)=6x²+46x+3

Maximum or minimum when f'(x)=0

6x²+46x+3=0

Using the Quadratic Formula: x=(-b+-squareroot(b²-4ac))/2a

x₁=-0.0658

x₂=-7.6

SK

Answered by Sanjana K. • Maths tutor

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