Differentiate 2x^3+23x^2+3x+5 and find the values of x for which the function f(x) is at either at a maximum or minimum point. (Don't need to specify which is which)
f(x)=2x3+23x2+3x+5
f'(x)=6x2+46x+3
Maximum or minimum when f'(x)=0
6x2+46x+3=0
Using the Quadratic Formula: x=(-b+-squareroot(b2-4ac))/2a
x1=-0.0658
x2=-7.6
SK
Related Maths A Level answers
All answers ▸If I had an equation with both 'x' and 'y' present, how would I find the gradient?
Find the equation of the tangent to the unit circle when x=sqrt(3)/2 (in the first quadrant)
How do I know if I am using the right particular integral when solving a differential equation
How would you derive y = function of x; for example: y = 3x^3 + x^2 + x